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OpenExam.HESI A2 · FOUNDATION PRACTICE

Mixed skills

Name: __________________________Date: __________________

10 original practice questions · Untimed · Follow each question’s response instructions

1. A model species has 6 chromosomes before DNA replication. After replication but before sister chromatids separate, each chromosome consists of two joined sister chromatids. Count chromosomes by their still-undivided centromeres. Which count fits this stage?

A. 6 chromosomes; 12 chromatidsB. 12 chromosomes; 12 chromatidsC. 3 chromosomes; 6 chromatidsD. 6 chromosomes; 6 chromatids
hesi-a2-pilot-q11

2. A rectangular display has width: length=3: 5 and a perimeter of 64 cm. What is its length?

A. 12 cmB. 20 cmC. 32 cmD. 40 cm
hesi-a2-pilot-q07

3. For the symbolic equation P₄+Cl₂→PCl₃, keep all chemical subscripts fixed. Which smallest whole-number coefficients, in the order P₄, Cl₂, PCl₃, balance the equation?

A. 1, 3, 4B. 4, 6, 4C. 1, 6, 2D. 1, 6, 4
hesi-a2-pilot-q09

4. Original passage: A walking-route team logs only paths its members have visited that month. Every completed visit in the current log occurred in dry weather. A blank line means the team has not yet visited that path; it is not a closure notice. The log contains no rainy-weather observations. Which conclusion follows from this information?

A. An unvisited path has worse conditions than every path with a completed entry.B. The dry-weather entries establish how those paths will perform during rain.C. Blank entries identify the paths that the team has closed to the public.D. The log does not establish the condition of an unvisited path.
hesi-a2-pilot-q02

5. In a simplified eukaryotic-cell model, a newly labeled secreted protein follows rough ER→Golgi→secretory vesicle. Labeling starts after transport from the ER to the Golgi has been completely blocked. Protein synthesis continues, and no labeled protein was present before the block. Over the short observation interval, which pattern is consistent with this model?

A. New label bypasses the ER and first appears inside outgoing secretory vesicles.B. New label appears in the ER but does not newly arrive in the Golgi.C. New label first appears in the Golgi, then moves backward into the ER.D. New label cannot appear in the ER because the Golgi makes this protein.
hesi-a2-pilot-q10

6. Choose the completion that makes all three listed actions parallel: “The volunteers agreed to label packets, to weigh samples, and _____.”

A. records arrivalsB. a record of arrivalsC. to record arrivalsD. recording arrivals
hesi-a2-pilot-q04

7. A workshop has 72 unmounted prints. It sends one third of them to an exhibition. It then mounts three eighths of the prints that remain. How many prints are still unmounted at the workshop?

A. 18 printsB. 30 printsC. 21 printsD. 45 prints
hesi-a2-pilot-q05

8. A paper human figure in anatomical position faces the observer directly, with no mirror or image reversal. A marker is on the figure’s anatomical left forearm. In this frontal view, which description is correct?

A. The marker appears on the observer’s right and becomes anatomically right.B. The marker appears on the observer’s left and becomes anatomically right.C. The marker appears on the observer’s left and remains anatomically left.D. The marker appears on the observer’s right and remains anatomically left.
hesi-a2-pilot-q12

9. An editor writes: “The specimen label is provisional. We will use it for now, but a second examination may require us to change it.” In this sentence, provisional most nearly means:

A. TemporaryB. PermanentC. UnrelatedD. Previous
hesi-a2-pilot-q03

10. A particle has 17 protons, 18 neutrons and 18 electrons. Which record gives its atomic number Z, mass number A and net charge?

A. Z=17; A=35; charge=−1B. Z=18; A=35; charge=−1C. Z=17; A=36; charge=−1D. Z=17; A=35; charge=+1
hesi-a2-pilot-q08
OpenExam.ANSWER KEY · KEEP SEPARATE

Answers & reasoning

1. 6 chromosomes; 12 chromatids · Choice A

The 6 undivided chromosome units remain 6 under the stated counting convention. Each has 2 sister chromatids, giving 6×2=12. DNA copying does not itself perform the later separation or a meiotic reduction.

hesi-a2-pilot-q11

2. 20 cm · Choice B

Write width=3 k and length=5 k. The perimeter is 2(3 k+5 k)=16 k=64, so k=4 cm and length=5×4=20 cm. Check: 2(12+20)=64 cm.

hesi-a2-pilot-q07

3. 1, 6, 4 · Choice D

One P₄ unit supplies 4 P atoms, requiring 4 PCl₃ units. Those products contain 4×3=12 Cl atoms, supplied by 6 Cl₂ units. The coefficients 1, 6, 4 have no common divisor greater than 1. Changing a subscript would change the chemical species.

hesi-a2-pilot-q09

4. The log does not establish the condition of an unvisited path. · Choice D

A blank entry establishes that no monthly visit is recorded, not whether the path is good, bad or closed. The dry-weather scope also cannot be extended to rainy conditions. Keep the conclusion within the supplied observations.

hesi-a2-pilot-q02

5. New label appears in the ER but does not newly arrive in the Golgi. · Choice B

The label is introduced only after the block, so there is no previously labeled Golgi pool. New synthesis can label the ER, but the stipulated block prevents that new cargo from reaching the Golgi. The inference concerns this model and interval, not every protein-trafficking route.

hesi-a2-pilot-q10

6. to record arrivals · Choice C

The three actions share the infinitive pattern: to label, to weigh, to record. The grammatical relationship, rather than the subject matter, determines the matching completion.

hesi-a2-pilot-q04

7. 30 prints · Choice B

One third of 72 is 24, leaving 48 at the workshop. Three eighths of 48 is 18 newly mounted. The unmounted remainder is 48−18=30 prints. The second fraction uses 48 as its base, not 72.

hesi-a2-pilot-q05

8. The marker appears on the observer’s right and remains anatomically left. · Choice D

Anatomical left belongs to the subject. For an unreversed frontal view of a facing figure, that side appears on the observer’s right. Changing the observer’s viewpoint does not rename the subject’s anatomical sides.

hesi-a2-pilot-q12

9. Temporary · Choice A

“For now” and the possibility of revision identify a temporary status pending confirmation. The context supplies the meaning without requiring outside knowledge about the specimen.

hesi-a2-pilot-q03

10. Z=17; A=35; charge=−1 · Choice A

Z counts 17 protons. A counts the nucleus: 17+18=35. Net charge in elementary-charge units is 17−18=−1. Changing electrons affects charge without changing the proton-defined element identity.

hesi-a2-pilot-q08

Original source-grounded practice. Content and reasoning checks are separate from professional educator review, which remains pending. Not an official exam paper.

OpenExam · Independent HESI A2 practiceFoundation pilot · No official score predictionSources & content notes