Study selected HESI A2 academic foundations through 12 original reasoning tasks, retrieval cards and a 14-day plan, with institution-specific requirement boundaries.
Read 10 original sample questions with worked explanations before opening the practice studio. These examples introduce selected topics from this HESI A2 foundation path.
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What this practice covers
Twelve actual guide units, not a complete course or 200-question bank. School-selected sections, timers, calculator rules, cut scores and admission criteria remain institution-specific. Not HESI Exit, NCLEX, clinical practice, dosing advice, secure-item recall or a pass/admission prediction. Qualified educator review pending.
12 original four-option foundation questions; not a full-length or official score simulation.
10 public examples12 question variants in the studio12 task families
Review status: Independent educator review and learner calibration are pending. Use these selected foundation examples alongside the coverage map and current official references.
Work out your answer first, then compare the explanation. This stable selection uses distinct task families across the available learning domains.
QUESTION 01Reading
Set your scope,then identify the main idea
Original passage: A seed archive once listed each collection under a familiar plant name. Staff found that a familiar name could refer to different plants in different regions. The new catalog links that name to a checked specimen and a collection record. Entries with uncertain identities are marked for further review. Visitor displays keep familiar names alongside verified identifiers, so visitors can still recognize the labels they know. The archive has not changed its storage capacity. Which statement best expresses the main idea?
The archive replaces specimen checking with a simpler system of familiar names.
The archive increases storage space before accepting more seed collections.
The archive improves identity tracking while preserving usable familiar labels.
The archive treats unresolved labels as evidence that the collections have failed.
Answer: The archive improves identity tracking while preserving usable familiar labels.
The linked specimens and records improve identity tracking, while the visitor labels retain familiar names. That statement explains both major strands. Storage expansion, reduced checking and a declaration of failure conflict with or exceed the passage.
Compare the other answer choices
The archive replaces specimen checking with a simpler system of familiar names.
The catalog adds checked specimens and verified identifiers; it does not replace checking with familiar names.
The archive increases storage space before accepting more seed collections.
The passage explicitly says storage capacity did not change; this substitutes a different project for the catalog work.
The archive treats unresolved labels as evidence that the collections have failed.
Uncertain identities are marked for review, not declared failed collections. This turns uncertainty into a stronger unsupported conclusion.
An editor writes: “The specimen label is provisional. We will use it for now, but a second examination may require us to change it.” In this sentence, provisional most nearly means:
Temporary
Permanent
Unrelated
Previous
Answer: Temporary
“For now” and the possibility of revision identify a temporary status pending confirmation. The context supplies the meaning without requiring outside knowledge about the specimen.
Compare the other answer choices
Permanent
A label that may change after review is not established permanently.
Unrelated
The passage concerns the label’s status, not whether it is related to the specimen.
Previous
The label is being used now; provisional does not mean that it has already been replaced.
Choose the completion that makes all three listed actions parallel: “The volunteers agreed to label packets, to weigh samples, and _____.”
records arrivals
a record of arrivals
to record arrivals
recording arrivals
Answer: to record arrivals
The three actions share the infinitive pattern: to label, to weigh, to record. The grammatical relationship, rather than the subject matter, determines the matching completion.
Compare the other answer choices
records arrivals
This finite verb does not match the preceding “to label” and “to weigh” phrases.
a record of arrivals
This noun phrase names a record rather than supplying a third parallel action.
recording arrivals
This gerund phrase changes form after two infinitive phrases.
Reference basis: Mills/LibreTexts—Parallelism. These are original learning questions, not questions reproduced from the references.
QUESTION 04Mathematics
Track which quantity a fraction acts on
A workshop has 72 unmounted prints. It sends one third of them to an exhibition. It then mounts three eighths of the prints that remain. How many prints are still unmounted at the workshop?
18 prints
30 prints
21 prints
45 prints
Answer: 30 prints
One third of 72 is 24, leaving 48 at the workshop. Three eighths of 48 is 18 newly mounted. The unmounted remainder is 48−18=30 prints. The second fraction uses 48 as its base, not 72.
Compare the other answer choices
18 prints
This is the number newly mounted, not the number still unmounted.
21 prints
This subtracts three eighths of the original 72 from the remaining 48, even though the second fraction applies to the remainder.
45 prints
This subtracts three eighths of 72 and ignores the prior exhibition allocation.
Separate proton identity,nuclear mass count and charge
A particle has 17 protons, 18 neutrons and 18 electrons. Which record gives its atomic number Z, mass number A and net charge?
Z=17; A=35; charge=−1
Z=18; A=35; charge=−1
Z=17; A=36; charge=−1
Z=17; A=35; charge=+1
Answer: Z=17; A=35; charge=−1
Z counts 17 protons. A counts the nucleus: 17+18=35. Net charge in elementary-charge units is 17−18=−1. Changing electrons affects charge without changing the proton-defined element identity.
Compare the other answer choices
Z=18; A=35; charge=−1
Atomic number counts protons, not neutrons or electrons.
Z=17; A=36; charge=−1
Mass number is protons plus neutrons: 17+18=35. Electrons are not added to mass number.
Z=17; A=35; charge=+1
There is one more electron than proton, so the net charge is negative, not positive.
Follow newly labeled cargo through a specified pathway
In a simplified eukaryotic-cell model, a newly labeled secreted protein follows rough ER→Golgi→secretory vesicle. Labeling starts after transport from the ER to the Golgi has been completely blocked. Protein synthesis continues, and no labeled protein was present before the block. Over the short observation interval, which pattern is consistent with this model?
New label bypasses the ER and first appears inside outgoing secretory vesicles.
New label appears in the ER but does not newly arrive in the Golgi.
New label first appears in the Golgi, then moves backward into the ER.
New label cannot appear in the ER because the Golgi makes this protein.
Answer: New label appears in the ER but does not newly arrive in the Golgi.
The label is introduced only after the block, so there is no previously labeled Golgi pool. New synthesis can label the ER, but the stipulated block prevents that new cargo from reaching the Golgi. The inference concerns this model and interval, not every protein-trafficking route.
Compare the other answer choices
New label bypasses the ER and first appears inside outgoing secretory vesicles.
The question stipulates the ER-to-Golgi pathway for this cargo; the block does not establish a bypass.
New label first appears in the Golgi, then moves backward into the ER.
This reverses the supplied route and ignores the complete ER-to-Golgi block.
New label cannot appear in the ER because the Golgi makes this protein.
The model says synthesis continues and places entry at rough ER, not protein synthesis in the Golgi.
Keep anatomical directions attached to the subject
A paper human figure in anatomical position faces the observer directly, with no mirror or image reversal. A marker is on the figure’s anatomical left forearm. In this frontal view, which description is correct?
The marker appears on the observer’s right and becomes anatomically right.
The marker appears on the observer’s left and becomes anatomically right.
The marker appears on the observer’s left and remains anatomically left.
The marker appears on the observer’s right and remains anatomically left.
Answer: The marker appears on the observer’s right and remains anatomically left.
Anatomical left belongs to the subject. For an unreversed frontal view of a facing figure, that side appears on the observer’s right. Changing the observer’s viewpoint does not rename the subject’s anatomical sides.
Compare the other answer choices
The marker appears on the observer’s right and becomes anatomically right.
The viewer’s right is not the subject’s anatomical right; the reference frame must remain attached to the figure.
The marker appears on the observer’s left and becomes anatomically right.
This reverses both the viewing relationship and the stated anatomical-side designation.
The marker appears on the observer’s left and remains anatomically left.
When subject and observer face each other, their left-right directions are opposite; no mirror reversal is stated.
Original passage: A walking-route team logs only paths its members have visited that month. Every completed visit in the current log occurred in dry weather. A blank line means the team has not yet visited that path; it is not a closure notice. The log contains no rainy-weather observations. Which conclusion follows from this information?
An unvisited path has worse conditions than every path with a completed entry.
The dry-weather entries establish how those paths will perform during rain.
Blank entries identify the paths that the team has closed to the public.
The log does not establish the condition of an unvisited path.
Answer: The log does not establish the condition of an unvisited path.
A blank entry establishes that no monthly visit is recorded, not whether the path is good, bad or closed. The dry-weather scope also cannot be extended to rainy conditions. Keep the conclusion within the supplied observations.
Compare the other answer choices
An unvisited path has worse conditions than every path with a completed entry.
No comparative condition data for an unvisited path are given; a blank line represents no visit.
The dry-weather entries establish how those paths will perform during rain.
The passage limits the observations to dry weather and supplies no rainy-weather results.
Blank entries identify the paths that the team has closed to the public.
The passage expressly distinguishes an unvisited path from a closure notice.
Reference basis: LibreTexts—Inferences. These are original learning questions, not questions reproduced from the references.
QUESTION 09Mathematics
Reverse a percentage change in the correct order
An archive subscription has a base charge. A 20% discount is applied to that base, then a fixed $6 dispatch charge is added. The final total is $46. What was the base charge?
$51.50
$32.00
$50.00
$48.00
Answer: $50.00
Remove the undiscounted dispatch charge first: 46−6=40. The $40 is 80% of the base, so 0.8 x=40 and x=50. Checking forward gives 0.8×50+6=46.
Compare the other answer choices
$51.50
Dividing 46 by 0.8 before subtracting 6 incorrectly treats the dispatch charge as discounted too.
$32.00
Multiplying the discounted $40 by 0.8 applies another discount rather than finding the original base.
$48.00
Adding 20% to the discounted $40 uses the reduced amount as the percentage base and does not reverse a 20% reduction.
Reference basis: Roy Simpson/LibreTexts—Percents. These are original learning questions, not questions reproduced from the references.
QUESTION 10Chemistry
Balance coefficients without changing the species
For the symbolic equation P₄+Cl₂→PCl₃, keep all chemical subscripts fixed. Which smallest whole-number coefficients, in the order P₄, Cl₂, PCl₃, balance the equation?
1, 3, 4
4, 6, 4
1, 6, 2
1, 6, 4
Answer: 1, 6, 4
One P₄ unit supplies 4 P atoms, requiring 4 PCl₃ units. Those products contain 4×3=12 Cl atoms, supplied by 6 Cl₂ units. The coefficients 1, 6, 4 have no common divisor greater than 1. Changing a subscript would change the chemical species.
Compare the other answer choices
1, 3, 4
Four PCl₃ units contain 12 chlorine atoms, but three Cl₂ units supply only 6.
4, 6, 4
Four P₄ units supply 16 phosphorus atoms while four PCl₃ units contain only 4.
1, 6, 2
The left side has 4 P and 12 Cl, while two PCl₃ units have 2 P and 6 Cl.
Start with the lesson linked to an unfamiliar topic, try a focused set in the practice studio, then return to the review cards. Your practice progress stays in this browser.
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Twelve actual guide units, not a complete course or 200-question bank. School-selected sections, timers, calculator rules, cut scores and admission criteria remain institution-specific. Not HESI Exit, NCLEX, clinical practice, dosing advice, secure-item recall or a pass/admission prediction. Qualified educator review pending.
Qualified educator review and learner calibration remain pending.
Check the exam provider's current information for registration, test rules and official preparation materials. The exam guide collects the relevant official references.
